Your answer to the question:
If I am riding in a car travelling at 60 miles per hour, how long will it take to go 100 feet? is below.
- If I am riding in a car travelling at 60 miles per hour, how long will it take to go 100 feet?
- You see, Billy, these kinds of Physics questions need to be approached carefully. You need to assemble all the equations and gracefully and logically apply transformations to determine the solution. In this case, we have several equations which may come into use, namely:
1/2*a*t^2 + v*t = d
a*t = v
v*t = d
What we do is we rearrange these equations until they mean something useful. After several minutes of calculations, which I will leave as an exercise for you to do at home, I obtained the following equation. (Note that I didn't use several simplifications that cannot be applied in this case because you are actually in the frame of reference of the car! Also, we are forced to take into account the rotation of the earth, so that we can correctly calculate the forces on the car.)
g^2 + 2*t^2/a^3 + v*a*(d-t) + -mc^2 - m0 + B*r*t^2 + 3*x0*y0 - x0^2*y0 - (4gt^2 - rcd + sqrt(7*v*t + a*x))= 5
Plugging in for the mass of an electron and the speed of light, I get the answer: 42. (This is odd, because the answer to this question seems to be the answer to life, the universe, and everything.)
Also, I failed to take into effect the polarizing effect of the Bose-Einstein cooling, and I am ignoring the effects of nearby neutron stars on distorting the space-time curve. This solution only applies if you consider the atmosphere to obey the laws of a simple gas.
Good luck exploring the fun world of physics!
- Submitted by:
- Professor Wonkins, PhD Physics